Cover
Every unguarded point must touch at least one guard. That is ordinary domination.
Exact theorem · Connected P₅-free graphs
Secure guards must answer attacks without leaving the network exposed. This certified 12-vertex graph proves that the best universal multiplier is at least 4/3; a companion all-orders theorem now proves it is exactly 4/3.
γs is the fewest secure guards; α is the largest set of points with no links between them.
The problem
Every unguarded point must touch at least one guard. That is ordinary domination.
If any unguarded point is attacked, an adjacent guard moves there.
After the move, every point must still touch a guard. That extra condition is security.
Interactive proof sketch
Exhaustive certificate
The claim does not rest on a picture. A simple independent verifier checks every relevant set of vertices and records why each three-guard set fails.
Open the machine-readable certificate ↗How it was found
Every eligible graph with up to 10 vertices obeyed γs ≤ α, so the stronger statement looked plausible.
Maximum independent sets, dominating paths, and a tempting dominating-edge lemma all failed as general proof routes.
The search required α = 3, no induced P₅, connectivity, and failure of every triple—without enumerating every graph.
The 12-vertex model was recognized as the complement of an icosahedron, then independently verified without the SAT clauses.
The status, precisely
This exact graph has α = 3 and γs = 4. That is a theorem established by exhaustive verification, not a conjecture. The published 3α/2 theorem still holds: 4 ≤ 4.5.
Searches exclude smaller examples, but this repository does not include a checkable SAT proof trace. Minimum order is therefore not claimed as a theorem here.
A companion all-orders proof gives γs ≤ α + 1 ≤ 4α/3 for α ≥ 3. This witness attains 4/3, so the coefficient is exact.
The sequel
The counterexample ruled out coefficient 1 without contradicting the published 3/2 theorem. The continuation proves the matching upper bound for every connected induced-P₅-free graph with α ≥ 3. Walk through the sharp theorem ↗
A second research track
A corrected FLIP2 experiment suggests they can—but the result is exploratory until tested on an untouched fourth backbone.